Building Abstractions with Data - Hierarchical Data and the Closure Property - Sequences as Conventional Interfaces - Sequence Operations - accumulate, map, append, length
Structure and Interpretation of Computer Programs: JavaScript Edition(Harold Abelson(著)、Gerald Jay Sussman(著)、Julie Sussman(著)、The MIT Press)のChapter 2(Building Abstractions with Data)、2.2(Hierarchical Data and the Closure Property)、2.2.3(Sequences as Conventional Interfaces)、Sequence Operations、Exercise 2.33の解答を求めてみる。
コード
function stringfy(x) {
if (is_null(x)) {
return "null";
}
if (is_pair(x)) {
return "[" + stringfy(head(x)) + ", " + stringfy(tail(x)) + "]";
}
return x.toString();
}
function pair(x, y) {
return [x, y];
}
function head(z) {
return z[0];
}
function tail(z) {
return z[1];
}
function is_pair(x) {
return Array.isArray(x);
}
function is_null(x) {
return x === null;
}
function list(...args) {
return args.length === 0 ?
null :
pair(args[0], list(...args.slice(1)));
}
function display(x) {
return console.log(stringfy(x));
}
function accumulate(op, initial, sequence) {
return is_null(sequence) ?
initial :
op(
head(sequence),
accumulate(op, initial, tail(sequence))
);
}
function map(f, sequence) {
return accumulate(
(x, y) => pair(f(x), y),
null,
sequence
);
}
function append(seq1, seq2) {
return accumulate(pair, seq2, seq1);
}
function length(sequence) {
return accumulate((x, y) => 1 + y, 0, sequence);
}
const sequence = list(1, 2, 3, 4, 5);
display(sequence);
display(map(x => x * x, sequence));
display(append(sequence, list(1, 2)));
display(length(list(0, 0, 0, 0, 0)));
入出力結果(Terminal, Zsh)
% node answer2.33.js
[1, [2, [3, [4, [5, null]]]]]
[1, [4, [9, [16, [25, null]]]]]
[1, [2, [3, [4, [5, [1, [2, null]]]]]]]
5
%